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Question
Henry's law constant for CH3Br(g) is 0.159 mol dm–3 bar–1 at 25°C. What is the solubility of CH3Br(g) in water at the same temperature and partial pressure of 0.164 bar?
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Solution
S = KHP
= 0.159 × 0.164
= 0.026076
= 0.0261
The Solubility of CH3Br(g) in water at same temperature and partial pressure of 0.164 bar will be 0.0261.
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