Question

Heat energy is given to 150 g of water, such that its temperature rises by 20 K. When the same amount of heat energy is given to a liquid X of mass 100 g its temperature rises by 80 K. Calculate (a) heat energy given to water (b) the specific heat capacity of liquid X.

[Take sp. heat capacity of water = 4.2 J g⁻¹ K⁻¹]

Answer 1

(a) Heat energy given to water = mcθ_R

 = 150 g × 4.2 J g⁻¹ K⁻¹ × 20 K

= 12600 J

(b) Heat energy given to liquid X = 12600 J

Now, Heat energy given to liquid X = mcθ_R

12600 J = 100 g × с × 80 K

\[{c} =\frac{12600 \mathrm{~J}}{100 \mathrm{~g} \times 80 \mathrm{~K}}\]

∴ c = 1.575 J g⁻¹ K⁻¹