Question

Half-life of a certain radioactive material is 8 hours.

Find the disintegration constant of this material.

Answer 1

`"T"_(1/2) = 0.693/lambda`   [λ = Disintegration constant]

`therefore lambda = 0.693/8`

`therefore lambda = 0.693/(8 xx 60 xx 60)` s^-1 = 2.41 × 10^-5 s^-1