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Question
Choose the most appropriate option.
Gold and copper are as heavy as water by 19 and 9 times respectively. The ratio in which these two metals be mixed so that the mixture is 17 times as heavy as water is:
Options
4:1
3:2
2:3
3:4
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Solution
4:1
Explanation:
Let the mass of 1 volume unit of water be 1.
Then,
1 volume unit of gold has a mass 19 and 1 volume unit of copper has mass 9.
Now let g be the volume of gold used and c be the volume of copper.
Then,
(19 g + 9 c)/ (g + c) = 17
19 g + 9 c = 17 g + 17 c
2 g = 8 c
`"g"/"c"=8/2=4/1`
∴ Required ratio = 4: 1
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