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Question
Given X ~ B(n, p) if p = 0.6 and E(X) = 6, find n and Var(X).
Sum
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Solution
Given: p = 0.6 and E(X) = 6
E(X) = np
∴ 6 = n × 0.6
n = `6/0.6`
n = 10
Now, q = 1 – p
= 1 – 0.6
= 0.4
∴ Var(X) = npq
= 10 × 0.6 × 0.4
= 2.4
Hence, n = 10, Var(X) = 2.4
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