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Question
Given that log 2 = a and log 3 = b, write `log sqrt(96)` in terms of a and b
Sum
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Solution
log 2 = a and log 3 = b
`log sqrt(96) = 1/2 log (96)`
= `1/2 log (2^5 xx 3)`
= `1/2(log 2^5 + log 3)` ...[log mn = log m + log n]
= `1/2 (5log 2 + log 3)` ..[log mn = nlog m]
= `(5"a" + "b")/2`
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