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Question
Given p.d.f. of a continuous r.v.X as
f(x) = `x^2/(3)` for –1 < x < 2
= 0, otherwise
then F(1) = _______.
Options
`(1)/(9)`
`(2)/(9)`
`(3)/(9)`
`(4)/(9)`
MCQ
Fill in the Blanks
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Solution
then F(1) = `underlinebb(2/9)`
Explanation:
F(1) = P(X ≤ 1)
= `int_(-1)^(1) x^2/(3)*dx`
= `(1)/(3) int_(-1)^(1) x^2*dx`
= `(1)/(9)[x^3]_(-1)^(1)`
= `(2)/(9)`
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Probability Distribution of a Continuous Random Variable
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