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Given \[P=\begin{bmatrix}1&2\\3&4\end{bmatrix}\] and \[Q=\begin{bmatrix}1&2\\3&5\end{bmatrix}\], why is \[P\ne Q\]?

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Question

Given \[P=\begin{bmatrix}1&2\\3&4\end{bmatrix}\] and \[Q=\begin{bmatrix}1&2\\3&5\end{bmatrix}\], why is \[P\ne Q\]?

Options

  • The matrices have different order.

  • The element in position \[(1,1)\] is different.

  • Both matrices have order \[2\times2\], but the element in position \[(2,2)\] is different: \[4\ne5\].

  • The element in position \[(1,2)\] is different.

MCQ
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Solution

Both \[P\] and \[Q\] have order \[2\times2\], so their corresponding elements can be compared. Their entries in position \[(2,2)\] are \[4\] and \[5\], which are not equal.

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