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​Given Number 1, 3, 5, ..., 101 Form an Ap with a = 1 and D = 2. Let Tn = 101. Then, 1 + (N − 1)2 = 101 ⇒ 1 + 2n − 2 = 101 ⇒ 2n = 102 ⇒ N = 51 Thus, Total Number of Outcomes = 51. - Mathematics

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Question

Cards marked with numbers 1, 3, 5, ..., 101 are placed in a bag and mixed thoroughly. A card is drawn at random from the bag. Find the probability that the number on the drawn card is a prime number less than 20.

Short/Brief Note
Sum
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Solution

​Given number 1, 3, 5, ..., 101 form an AP with a = 1 and d = 2.
Let Tn = 101. Then,
1 + (n − 1)2 = 101
⇒ 1 + 2n  − 2 = 101
⇒ 2n = 102
⇒ n = 51

Thus, total number of outcomes = 51.

Let E2 be the event of getting a prime number less than 20.

Out of these numbers, prime numbers less than 20 are 3, 5, 7, 11, 13, 17 and 19.

Thus, number of favourable outcomes = 7.

∴ P(getting a prime number less than 20) = P(E2) = `("Number of outcomes favourable to" E_2)/"Number of all possible outcomes"`

`= 7/51`

Thus, the probability that the number on the drawn card is a prime number less than 20 is `7/51`.

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Chapter 15: Probability - Exercise 15B [Page 696]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 15 Probability
Exercise 15B | Q 6.2 | Page 696
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