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Question
Given log2 x = m. Express 2m - 3 in terms of x.
Sum
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Solution
log2x = m
⇒ 2m = x
Consider 2m = x
⇒ `2^m/2^3=x/2^3`
⇒ `2^(m-3)= x/8`
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Interchanging Logarithmic and Exponential Forms
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