Given Log2 X = M. Express 2m - 3 in Terms of X.

Given log₂x = m. Express 2^{m - 3} in terms of x.

Sum

log₂x = m

⇒ 2^m = x
Consider 2^m = x

⇒ `2^m/2^3=x/2^3`

⇒ `2^(m-3)= x/8`

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Interchanging Logarithmic and Exponential Forms

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Chapter 8: Logarithms - Exercise 8 (A) [Page 104]

Chapter 8 Logarithms
Exercise 8 (A) | Q 9.1 | Page 104

Express the following in logarithmic form:

5³ = 125

Express the following in logarithmic form:

`3^-2 = 1/9`

Express the following in logarithmic form : `(81)^(3/4) = 27`

Solve for x : log₁₀ x = -2.

Find the logarithm of : 32 to the base 4

Find the logarithm of : 0.125 to the base 2

State, true or false : If log₁₀ x = a, then 10^x = a.

State, true or false : If x^y = z, then y = log_zx .

Find x, if : log₅ (x - 7) = 1

If log_am = n, express a^{n - 1} in terms of a and m.