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Given below is the distribution of total household expenditure of 200 manual workers in a city: Expenditure (in Rs) 1000 – 1500 1500 – 2000 2000 – 2500 2500 – 3000 3000 – 3500 3500 – 4000 4000 – 4500

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Question

Given below is the distribution of total household expenditure of 200 manual workers in a city:

Expenditure (in Rs) 1000 – 1500 1500 – 2000 2000 – 2500 2500 – 3000 3000 – 3500 3500 – 4000 4000 – 4500 4500 – 5000
Number of manual
workers
24 40 31 28 32 23 17 5

Find the average expenditure done by maximum number of manual workers.

Sum
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Solution

As the class 1500-2000 has the maximum frequency, it is the modal class.
Now, `x_k = 1500, h = 500, f_k = 40, f_k-1 = 24, f_k+1 = 31`

∴ Mode, `M_0 = x_k + {ℎ ×((f_k− f_k−1))/((2f_k− f_k−1−f_k+1))}`

 = 1500 + `{500 xx ((40-24))/((2 xx40-24-31))}`

 = `1500 + {500xx 16/25}`

= (1500 + 320)

= 1820

Hence, mode = Rs 1820

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Chapter 18: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive - EXERCISE 18C [Page 878]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 18 Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
EXERCISE 18C | Q 5. | Page 878
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