Question

Given A = `[(-3, 6),(0, -9)]` and A^t is its transpose matrix. Find 2A + 3A^t 

Answer 1

A = `[(-3, 6),(0, -9)]`

A^t = `[(-3, 0),(6, -9)]`

2A + 3A^t = `2[(-3, 6),(0, -9)] + 3[(-3, 0),(6, -9)]`

= `[(-6,12),(0, -18)] + [(-9, 0),(18, -27)]`

= `[(-6 - 9, 12 + 0),(0 + 18, -18 - 27)]`

= `[(-15, 12),(18, -45)]`