Question

Given a = 3 sec² θ and b = 3 tan² θ – 2. The value of (a – b) is ______.

Options

• 1

• 2

• 3

• 5

Answer 1

Given a = 3 sec² θ and b = 3 tan² θ – 2. The value of (a – b) is 5.

Explanation:

a – b = 3 sec²θ – (3 tan²θ – 2) 

= 3(sec²θ – tan²θ) + 2 

Using sec²θ – tan²θ = 1 gives 3 × 1 + 2 = 5.