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Question
Given A = `[(1, 1),(8, 3)]`, evaluate A2 – 4A
Sum
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Solution
A = `[(1, 1),(8, 3)]`
A2 – 4A =`[(1, 1),(8, 3)] [(1, 1),(8, 3)] - 4[(1, 1),(8, 3)]`
= `[(1 + 8, 1 + 3),(8 + 24, 8 + 9)] - [(4, 4),(32, 12)]`
= `[(9, 4),(32, 17)] - [(4, 4),(32 , 12)]`
= `[(9 - 4, 4 - 4),(32 - 32, 17 - 12)]`
= `[(5, 0),(0, 5)]`.
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