Advertisements
Advertisements
Question
Give the expression for the magnitude of its electric dipole moment and the direction.
Advertisements
Solution
- The magnitude of the dipole moment is given by the product of the magnitude of one of the charges and the distance between them.
`|vec "P"|` = 2qa
`vec "P" = "qr"_+ + (- "q") vec "r"_-`
where r̂+ is the position of vector of +1 from the origin and r̂– is the position vector of -q from the origin
`vec "P" = "qai" - "qa"(- hat"i") = 2 "qai"` - It is a vector quantity having direction along the dipole axis -q to +q.
- Unit: coulomb metre (Cm).
APPEARS IN
RELATED QUESTIONS
Two identical point charges of magnitude –q are fixed as shown in the figure below. A third charge +q is placed midway between the two charges at the point P. Suppose this charge +q is displaced a small distance from the point P in the directions indicated by the arrows, in which direction(s) will +q be stable with respect to the displacement?
An electric dipole is placed at an alignment angle of 30° with an electric field of 2 × 105 NC-1. It experiences a torque equal to 8 Nm. The charge on the dipole if the dipole length is lcm is ______.
Define ‘electric dipole’.
Write the general definition of electric dipole moment for a collection of point charge.
Calculate the electric field due to a dipole on its axial line and equatorial plane.
Derive an expression for the torque experienced by a dipole due to a uniform electric field.
Consider an electron travelling with a speed VΦ and entering into a uniform electric field `vec"E"` which is perpendicular to `vec"V"_0` as shown in the Figure. Ignoring gravity, obtain the electron’s acceleration, velocity and position as functions of time.
