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Question
General solution of tan 5θ = cot 2θ is
Options
θ = `(npi)/7 + pi/4`
θ = `(npi)/7 + pi/5`
θ = `(npi)/7 + pi/2`
θ = `(npi)/7 + pi/3`
MCQ
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Solution
θ = `(npi)/7 + pi/4`
Explanation:
Given, tan 5θ = cot 2θ
⇒ `tan 5theta = tan(pi/2 - 2theta)` ......`[because tan(pi/2 - theta) = cot theta]`
⇒ `5theta = npi + pi/2 - 2theta`
⇒ `7theta = npi + pi/2`
⇒ `theta = (npi)/7 + pi/14`.
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