Question

From the figure, given below, calculate the length of CD.

Answer 1

In right ΔACB, we have

`tan theta = (AB)/(BC)`

`\implies tan 47^circ = (AB)/15`

`\implies 1.0724 = (AB)/15`

∴ AB = 1.0724 × 15

= 16.0860 m

= 16.09 m.

And in right ΔADE, we have

`tan 22^circ = (AE)/(DE)`

`\implies 0.4040 = (AE)/15`

∴ AE = 15 × 0.4040

= 6.0600

= 6.06 m.

∴ CD = EB

= AB – AE

= 16.09 – 6.06

= 10.03 m