English

From \[\begin{bmatrix}2a+b&a-2b\\5c-d&4c+3d\end{bmatrix}=\begin{bmatrix}4&-3\\11&24\end{bmatrix},\] which equation is obtained by equating the corresponding elements in position \[(2,1)\]?

Advertisements
Advertisements

Question

From \[\begin{bmatrix}2a+b&a-2b\\5c-d&4c+3d\end{bmatrix}=\begin{bmatrix}4&-3\\11&24\end{bmatrix},\] which equation is obtained by equating the corresponding elements in position \[(2,1)\]?

Options

  • \[2a+b=4\]

  • \[5c-d=11\]

  • \[a-2b=-3\]

  • \[4c+3d=24\]

MCQ
Advertisements

Solution

The entry in row 2 and column 1 is \[5c-d\] in the first matrix. Its corresponding element is \[11\] in the second matrix.

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×