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Question
From a pack of 52 cards, all aces and all kings are removed. A card is drawn at random from the remaining cards. Find the probability that the card so drawn is
- a face card.
- a card of red colour.
Sum
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Solution
Given: Total cards = 52
Cards removed = 4 Aces + 4 Kings = 8 cards
\[ \text{Remaining total cards, } n(S) = 52 - 8 = 44 \]
(i) A face card: Original face cards = 12 (4 Kings, 4 Queens, 4 Jacks).
Since all 4 Kings are removed, only Queens and Jacks remain.
Number of remaining face cards = `(4 + 4 = 8)`
\[ P(\text{face card}) = \dfrac{8}{44} = \dfrac{2}{11} \]
(ii) A card of red colour: Original red cards = 26
Red cards removed = 2 red Aces + 2 red Kings = 4 cards
Remaining red cards = `(26 - 4 = 22)`
\[ P(\text{red card}) = \dfrac{22}{44} = \dfrac{1}{2} \]
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