Advertisements
Advertisements
Question
From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed. (as shown in the following figure). Find the area of the remaining sheet. (Take `pi = 22/7`)

Advertisements
Solution
Area of bigger circle = `22/7 xx 14 xx 14`
= 616 cm2
Area of 2 small circles = `2 xx pir^2`
= `2 xx 22/7 xx 3.5 xx 3.5`
= 77 cm2
Area of rectangle = Length × Breadth
= 3 × 1
= 3 cm2
Remaining area of sheet = 616 - 77 - 3
= 536 cm2
APPEARS IN
RELATED QUESTIONS
The circumference of a circle is 31.4 cm. Find the radius and the area of the circle? (Take π = 3.14)
In Figure 5, a circle is inscribed in a triangle PQR with PQ = 10 cm, QR = 8 cm and PR =12 cm. Find the lengths of QM, RN and PL ?

In the following figure, the square ABCD is divided into five equal parts, all having same area. The central part is circular and the ines AE, GC, BF and HD lie along the diagonals AC and BD of the square. If AB = 22 cm, find:
the circumference of the central part.

In the following figure, O is the centre of a circular arc and AOB is a straight line. Find the perimeter and the area of the shaded region correct to one decimal place. (Take π = 3.142)

In the following figure, ABCD is a trapezium of area 24.5 cm2 , If AD || BC, ∠DAB = 90°, AD = 10 cm, BC = 4 cm and ABE is quadrant of a circle, then find the area of the shaded region. [CBSE 2014]

Write the area of the sector of a circle whose radius is r and length of the arc is l.
The area of a circular path of uniform width h surrounding a circular region of radius r is
The minute hand of a clock is 15 cm long. Calculate the area swept by it in 20 minutes.
In the given figure, PQRS represents a flower bed. If OP = 21 m and OR = 14 m, find the area of the flower bed.

The floor of the circular swimming pool whose radius is 7 m has to be cemented at the rate of ₹ 18 per m2. Find the total cost of cementing the floor
