Advertisements
Advertisements
Question
The floor of the circular swimming pool whose radius is 7 m has to be cemented at the rate of ₹ 18 per m2. Find the total cost of cementing the floor
Advertisements
Solution
Radius of the circular swimming pool r = 7 m
Area of the circular swimming pool A = πr2 sq.units
= `22/7 xx 7 xx 7 "m"^2`
= 154 m2
Cost of cementing a m2 floor = ₹ 18
Cost of cementing 154 m2 floor = ₹ 18 × 154
= ₹ 2,772
APPEARS IN
RELATED QUESTIONS
A room is 16 m long and 13.5 m broad. Find the cost of covering its floor with 75-m-wide carpet at ₹ 60 per metre.
The floor of a rectangular hall is 24 m long and 18 m wide. How many carpets, each of length 2.5 m and breadth 80 cm, will be required to cover the floor of the hall?
The cost of harvesting a square field at ₹ 900 per hectare is ₹ 8100. Find the cost of putting a fence around it at ₹ 18 per meter.
A square of diagonal 8 cm is inscribed in a circle. Find the area of the region lying outside the circle and inside the square.
Find the area of the following figure, in square cm, correct to one place of decimal. (Take π = 22/7).
In the following figure, from a rectangular region ABCD with AB = 20 cm, a right triangle AED with AE = 9 cm and DE = 12 cm, is cut off. On the other end, taking BC as diameter, a semicircle is added on outside' the region. Find the area of the shaded region. [Use π =]`22/7` [CBSE 2014]
Find the area of the shaded region in the following figure, if AC = 24 cm, BC = 10 cm and O is the centre of the circle. (Use π = 3.14)
A circle is inscribed in an equilateral triangle ABC is side 12 cm, touching its sides (the following figure). Find the radius of the inscribed circle and the area of the shaded part.
In the following figure, the area of the segment PAQ is
Four equal circles, each of radius 5 cm, touch each other, as shown in the figure. Find the area included between them.
