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Four cows are tethered at the four corners of a square field of side 50 m such that the each can graze the maximum unshared area. What area will be left ungrazed? [Take π = 3.14.]

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Question

Four cows are tethered at the four corners of a square field of side 50 m such that the each can graze the maximum unshared area. What area will be left ungrazed? [Take π = 3.14.]

Sum
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Solution

Let r be the radius of the circle.

Thus, we have ;

`r = 50/2 "m"`

= 25 m

Area left ungrazed = (Area of the square) - 4(Area of the sector where r = 25 m and θ = 90°)

`=|(50xx50)-4(3.14xx25xx25xx90/360)|"m"^2`

`=|2500-(4xx(19625)/4)|"m"^2`

`=(2500 - 1962.5)  "m"^2`

= 537.5 m2

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Chapter 16: Area of Circle, Sector and Segment - TEST YOURSELF [Page 765]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 16 Area of Circle, Sector and Segment
TEST YOURSELF | Q 19. | Page 765
R.S. Aggarwal Mathematics [English] Class 10
Chapter 16 Area of Circle, Sector and Segment
EXERCISE 16A | Q 25. | Page 732
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