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Question
For \(x=a\cos^3\theta\) and \(y=a\sin^3\theta\), which expression gives \(\frac{dy}{dx}\) in terms of \(x\) and \(y\)?
Options
\(\sqrt[3]{\frac{x}{y}}\)
\(\sqrt[3]{\frac{y}{x}}\)
\(-\sqrt[3]{\frac{y}{x}}\)
\(-\sqrt[3]{\frac{x}{y}}\)
MCQ
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Solution
From the parametric equations, \(\tan\theta=\sqrt[3]{\frac{y}{x}}\). Therefore, since \(\frac{dy}{dx}=-\tan\theta\), the derivative is \(-\sqrt[3]{\frac{y}{x}}\).
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