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For \(x=a\cos^3\theta\) and \(y=a\sin^3\theta\), what is \(\frac{dy}{dx}\) in terms of \(\theta\)?

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Question

For \(x=a\cos^3\theta\) and \(y=a\sin^3\theta\), what is \(\frac{dy}{dx}\) in terms of \(\theta\)?

Options

  • \(-\cot\theta\)

  • \(\cot\theta\)

  • \(\tan\theta\)

  • \(-\tan\theta\)

MCQ
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Solution

Using the parametric formula, \(\frac{dy}{dx}=\frac{3a\sin^2\theta\cos\theta}{-3a\cos^2\theta\sin\theta}\). Simplifying gives \(\frac{dy}{dx}=-\tan\theta\).

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