Advertisements
Advertisements
Question
For \[v\ne0\], what is the derivative of \[\frac{u}{v}\]?
Options
\[\left(\frac{u}{v}\right)'=\frac{u'}{v'}\]
\[\left(\frac{u}{v}\right)'=\frac{u'v+uv'}{v^2}\]
\[\left(\frac{u}{v}\right)'=\frac{u'v-uv'}{v}\]
\[\left(\frac{u}{v}\right)'=\frac{u'v-uv'}{v^2}\]
MCQ
Advertisements
Solution
The quotient rule has numerator \[u'v-uv'\] and denominator \[v^2\]. The condition \[v\ne0\] is required for the quotient to be defined.
shaalaa.com
Is there an error in this question or solution?
