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For \[v\ne0\], what is the derivative of \[\frac{u}{v}\]?

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Question

For \[v\ne0\], what is the derivative of \[\frac{u}{v}\]?

Options

  • \[\left(\frac{u}{v}\right)'=\frac{u'}{v'}\]

  • \[\left(\frac{u}{v}\right)'=\frac{u'v+uv'}{v^2}\]

  • \[\left(\frac{u}{v}\right)'=\frac{u'v-uv'}{v}\]

  • \[\left(\frac{u}{v}\right)'=\frac{u'v-uv'}{v^2}\]

MCQ
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Solution

The quotient rule has numerator \[u'v-uv'\] and denominator \[v^2\]. The condition \[v\ne0\] is required for the quotient to be defined.

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