Question

For two capacitors in series, which expression gives the voltage across the second capacitor?

Options

• \[V_2=\frac{C_2}{C_1+C_2}\cdot V\]

• \[V_2=\frac{C_1+C_2}{C_1}\cdot V\]

• \[V_2=\frac{C_1}{C_1+C_2}\cdot V\]

• \[V_2=(C_1+C_2)V\]

Answer 1

The voltage across the second capacitor is given by the first capacitor's capacitance divided by the sum of both capacitances, multiplied by the total voltage. The two individual voltage drops add to \[V\].