Question

For the standard form \[ 6\sqrt{3}x^{2} + 7x - \sqrt{3} = 0 \], what is the product of the middle-term numbers?

Options

• \[ 6\sqrt{3} \times 7 = 42\sqrt{3} \]

• \[ 6\sqrt{3} \times \sqrt{3} = 18 \]

• \[ 6\sqrt{3} \times (-\sqrt{3}) = -18 \]

• \[ 7 \times (-\sqrt{3}) = -7\sqrt{3} \]

Answer 1

The product of middle-term numbers equals \[ a \times c \]. Here \( a = 6\sqrt{3} \) and \( c = -\sqrt{3} \), so \[ 6\sqrt{3} \times (-\sqrt{3}) = -18 \].