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Question
For the reaction \[\ce{3A -> 2B}\], rate of reaction `-("d"["A"])/"dt"` is equal to ______.
Options
`(+3)/2 ("d"["B"])/"dt"`
`(+2)/3 ("d"["B"])/"dt"`
`(+1)/3 ("d"["B"])/"dt"`
`(+1)/2 ("d"["B"])/"dt"`
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Solution
For the reaction \[\ce{3A -> 2B}\], rate of reaction `-("d"["A"])/"dt"` is equal to `bbunderline((+3)/2 ("d"["B"])/"dt")`.
Explanation:
Rate of reaction = `(-1)/3 ("d"["A"])/"dt" = (+1)/2 ("d"["B"])/"dt"`
`(-"d"["A"])/"dt" = (+3"d"["B"])/(2"dt")`
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