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Question
For the G.P., if r = `1/3`, a = 9, find t7.
Sum
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Solution
Given, r = `1/3`, a = 9
tn= arn–1
∴ t7 = `9 xx (1/3)^(7 - 1)`
= `9xx(1/3)^6`
= `9xx1/729`
∴ t7 = `1/81`
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