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Question
For the given frequency distribution, the adjustment factor is:
| C.I. | 30-34 | 34-38 | 38-42 |
| f | 8 | 10 | 8 |
Options
\[\frac{38-34}{2}\]
\[\frac{30+34}{2}\]
0
34 + 38
MCQ
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Solution
0
Explanation:
By formula,
\[\text{Adjustment factor} = \frac{\text{Lower limit of one class} - \text{Upper limit of previous class}}{2}\]
The given classes (30-34, 34-38, 38-42) are already in continuous (exclusive) form, as the upper limit of each class is equal to the lower limit of the next class.
\[\Rightarrow \text{Adjustment factor} = \frac{34 - 34}{2} = \frac{0}{2} = 0.\]
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