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For the following frequency distribution, find: i. median ii. lower quartile iii. upper quartile iv. interquartile range Variate 10 18 20 22 25 27 28 Frequency 4 6 8 9 7 8 6 - Mathematics

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Question

For the following frequency distribution, find:

  1. median 
  2. lower quartile
  3. upper quartile 
  4. interquartile range
Variate 10 18 20 22 25 27 28
Frequency 4 6 8 9 7 8 6
Sum
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Solution

To find the median and quartiles, we first need to calculate the cumulative frequency (cf) for the given data set. 

Frequency distribution table

Variable (x) Frequency (f) Cumulative Freuqency (cf)
10 4 4
18 6 10
20 8 18
22 9 27
25 7 34
27 8 42
28 6 48

The total number of observations is N = 48.

i. Median

Since N is even 48, the median is the average of the `(N/2)^(th)` and `(N/2 + 1)^(th)` terms.

Position: `48/2` = 24th and 25th terms.

Looking at the cumulative frequency table, the values from the 19th to the 27th position are all 22.

Median = 22

ii. Lower Quartile (Q1)

For a discrete frequency distribution, the lower quartile is the value at the `(N/4)^(th)` position.

Position: `48/4` = 12th term.

The cumulative frequency just greater than 12 is 18, which corresponds to the variate 20.

Lower Quartile (Q1) = 20

iii. Upper Quartile (Q3)

The upper quartile is the value at the `((3N)/4)^(th)` position.

Position: `(3 xx 48)/4` = 36th term

The cumulative frequency just greater than 36 is 42, which corresponds to the variate 27.

Upper Quartile (Q3) = 27

iv. Interquartile Range (IQR)

The interquartile range is the difference between the upper and lower quartiles.

Formula: IQR = Q3 – Q1

Calculation: 27 – 20 = 7

Interquartile Range = 7

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Chapter 21: Measures of central tendency - Exercise 21B [Page 468]

APPEARS IN

Nootan Mathematics [English] Class 10 ICSE
Chapter 21 Measures of central tendency
Exercise 21B | Q 10. | Page 468
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