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For the differential equation \[y''' + y^{2} + e^{y'} = 0\], what is the order?

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Question

For the differential equation \[y''' + y^{2} + e^{y'} = 0\], what is the order?

Options

  • Order = 4

  • Order = 3

  • Order = 2

  • Order = 1

MCQ
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Solution

The order is determined by the highest order derivative appearing in the equation. In this equation, the highest order derivative is \[y'''\] (third-order derivative). Therefore, the order is 3.

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