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Question
For the coagulation of negative sol, the species below that has the highest flocculating power is:
Options
\[\ce{SO^{2-}4}\]
Ba+2
Na+
\[\ce{PO^{3-}4}\]
MCQ
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Solution
Ba+2
Explanation:
For the coagulation of a negative sol, the coagulating ion is a cation. According to the Hardy-Schulze rule, flocculating power increases with the valency of the ion. Among the given species, Ba+2 (divalent cation) has higher flocculating power than Na+ (monovalent) and the anions \[\ce{SO^{2-}4}\] or \[\ce{PO^{3-}4}\], which are not effective for negative sol coagulation. Therefore, Ba+2 has the highest flocculating power for coagulating a negative sol.
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