Question

For the charging capacitor, what does \[\varepsilon_0\frac{d\Phi_E}{dt}\] equal?

Options

• The charge \[q\]

• The electric field \[E\]

• Zero

• The conduction current \[i_c\]

Answer 1

Differentiating the electric flux gives the conduction current divided by \[\varepsilon_0\]. Multiplying by \[\varepsilon_0\] therefore gives \[i_c\].