Question

For \[\text{C}(x)=0.005x^3-0.02x^2+30x+5000\], what is the marginal cost when \[x=3\]?

Options

• \[MC=\text{₹}30.00\]

• \[MC\approx\text{₹}30.02\]

• \[MC=\text{₹}5000\]

• \[MC=\text{₹}30.12\]

Answer 1

At \[x=3\], \[MC=0.015(3^2)-0.04(3)+30=0.135-0.12+30=30.015\].
Thus, the required marginal cost is \[MC\approx\text{₹}30.02\].