Question

For \[P(E)=\frac{1}{3}\] and \[P(F)=\frac{1}{2}\], what is \[P(E)P(F)\]?

Options

• \[P(E)P(F)=\frac{1}{3}-\frac{1}{2}=\frac{1}{6}\]

• \[P(E)P(F)=\frac{1}{3}+\frac{1}{2}=\frac{5}{6}\]

• \[P(E)P(F)=\frac{1}{3}\times\frac{1}{2}=\frac{1}{6}\]

• \[P(E)P(F)=\frac{1}{2}\times\frac{1}{2}=\frac{1}{4}\]

Answer 1

Multiply the probabilities of E and F: \[\frac{1}{3}\times\frac{1}{2}=\frac{1}{6}\]. This equals \[P(E\cap F)\].