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Question
For \[\int\frac{\sin x}{\sin(x+a)}\,dx\], which substitution gives \[dx=dt\]?
Options
\[\sin(x+a)=t\]
\[x+a=t\]
\[\cos(x+a)=t\]
\[x-a=t\]
MCQ
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Solution
Put \[x+a=t\], so \[x=t-a\]. Differentiating gives \[dx=dt\].
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