Question

For \(f(x)=\frac{x-1}{x+1}\), what is the domain of \(f\)?

Options

• \(\mathbb{R}-\{-1\}\)

• \(\mathbb{R}-\{0\}\)

• \(\mathbb{R}-\{1\}\)

• \(\mathbb{R}\)

Answer 1

The denominator \(x+1\) cannot be zero, so \(x\neq-1\). Hence, the domain is \(D_f=\mathbb{R}-\{-1\}\).