Question

For \(f(x)=4x^2+1\) and \(g(x)=\frac{1}{x+2}\), what is \((g\circ f)(2)\)?

Options

• \(\frac{1}{19}\)

• \(\frac{1}{17}\)

• 5

• 17

Answer 1

First, \(f(2)=4(2)^2+1=17\). Then \(g(17)=\frac{1}{17+2}=\frac{1}{19}\), so \((g\circ f)(2)=\frac{1}{19}\).