Question

For \(f(x)=4x^2+1\) and \(g(x)=\frac{1}{x+2}\), what is \((f\circ g)(-1)\)?

Options

• 17

• \(\frac{1}{19}\)

• 1

• 5

Answer 1

First, \(g(-1)=\frac{1}{-1+2}=1\). Applying \(f\) gives \(f(1)=4(1)^2+1=5\), so \((f\circ g)(-1)=5\).