Question

For \[f(x)=12x^{\frac{4}{3}}-6x^{\frac{1}{3}}\], which critical point is obtained from \[2(8x-1)=0\]?

Options

• \[x=\frac{1}{8}\]

• \[x=0\]

• \[x=1\]

• \[x=-1\]

Answer 1

Solving \[2(8x-1)=0\] gives \[8x-1=0\]. Hence, \[x=1/8\] is a critical point.