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Question
For any angle θ, state the value of: sin2 θ + cos2 θ
Sum
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Solution
sin2 θ =cos2 θ
= sin2 θ + 1 – sin2θ = 1
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Is there an error in this question or solution?
For any angle θ, state the value of: sin2 θ + cos2 θ
sin2 θ =cos2 θ
= sin2 θ + 1 – sin2θ = 1