Question

For an ideal transformer with \[\frac{V_s}{V_p}=3\], what is \[\frac{I_p}{I_s}\]?

Options

• \[\frac{1}{3}\]

• \[9\]

• \[3\]

• \[1\]

Answer 1

The ideal-transformer current ratio satisfies \[\frac{I_p}{I_s}=\frac{V_s}{V_p}\]. A voltage ratio of \[3\] therefore gives a primary-to-secondary current ratio of \[3\].