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For a square matrix \(A=[a_{ij}]\) of order \(n\), what is the minor \(M_{ij}\) of \(a_{ij}\)?

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Question

For a square matrix \(A=[a_{ij}]\) of order \(n\), what is the minor \(M_{ij}\) of \(a_{ij}\)?

Options

  • The determinant of the original square matrix of order \(n\).

  • \((-1)^{i+j}\) times the determinant obtained by deleting the \(i\)-th row and the \(j\)-th column.

  • The determinant obtained by deleting the \(j\)-th row and the \(i\)-th column in which element \(a_{ij}\) lies.

  • The determinant obtained by deleting the \(i\)-th row and the \(j\)-th column in which element \(a_{ij}\) lies.

MCQ
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Solution

The minor \(M_{ij}\) is formed by deleting the \(i\)-th row and \(j\)-th column containing \(a_{ij}\). The determinant of the remaining matrix is \(M_{ij}\).

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