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For a full dielectric slab filling the gap, how does the potential difference change?

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Question

For a full dielectric slab filling the gap, how does the potential difference change?

Options

  • \[V=\frac{K}{V_0}\]

  • \[V=V_0-K\]

  • \[V=KV_0\]

  • \[V=\frac{V_0}{K}\]

MCQ
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Solution

The slab fills the gap, so the separation remains \[d\] and \[V=Ed\]. Because the field is reduced by a factor of \[K\], the potential difference is also reduced by that factor.

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