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Question
For a full dielectric slab filling the gap, how does the potential difference change?
Options
\[V=\frac{K}{V_0}\]
\[V=V_0-K\]
\[V=KV_0\]
\[V=\frac{V_0}{K}\]
MCQ
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Solution
The slab fills the gap, so the separation remains \[d\] and \[V=Ed\]. Because the field is reduced by a factor of \[K\], the potential difference is also reduced by that factor.
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