Question

For a first order reaction, the plot of log k against 1/T is a straight line. The slope of the line is equal to ______.

Options

• `-E_a/R`

• `-2.303/(E_aR)`

• `-E_a/2.303`

• `-E_a/(2.303R)`

Answer 1

For a first order reaction, the plot of log k against 1/T is a straight line. The slope of the line is equal to `\bb(\underline(-E_a/(2.303R)))`.

Explanation:

`k = Ae^(-E/(RT)) log k`

`= log A - E_a/(2.303R), 1/T`

`= (-E_a)/(2.303R)`