Question

For a coil of \(N\) turns, how does the field compare with the field of one loop?

Options

• \(N\) loops produce \(N\) times the field of one loop

• \(N\) loops produce the same field as one loop

• \(N\) loops produce \(\frac{1}{N}\) times the field of one loop

• \(N\) loops produce \(N^2\) times the field of one loop

Answer 1

The magnetic field contributions from the turns add together. Therefore, a coil of \(N\) turns produces \(N\) times the field of one loop.