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For \[A=\begin{bmatrix}1&2&3\\2&3&1\end{bmatrix}\] and \[B=\begin{bmatrix}3&-1&3\\-1&0&2\end{bmatrix}\], which matrix is \[-B\]?

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Question

For \[A=\begin{bmatrix}1&2&3\\2&3&1\end{bmatrix}\] and \[B=\begin{bmatrix}3&-1&3\\-1&0&2\end{bmatrix}\], which matrix is \[-B\]?

Options

  • \[\begin{bmatrix}1&-3\\0&-1\\2&3\end{bmatrix}\]

  • \[\begin{bmatrix}-3&1&-3\\1&0&-2\end{bmatrix}\]

  • \[\begin{bmatrix}3&1&3\\1&0&2\end{bmatrix}\]

  • \[\begin{bmatrix}-3&-1&-3\\-1&0&-2\end{bmatrix}\]

MCQ
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Solution

The negative of a matrix is obtained by changing the sign of each corresponding entry. Thus \[3,-1,3,-1,0,2\] become \[-3,1,-3,1,0,-2\].

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