Question

Five consecutive even integers are such that two times the second integer is ten more than the 5th integer. Find the sum of all five integers.

Options

• 90

• 88

• 92

• 94

Answer 1

90

Explanation:

Sum of all 5 integers

= n + (n + 2) + (n + 4) + (n + 6) + (n + 8) = 5n + 20

Also, we are given 2(n + 2) = (n + 8) + 10

⇒ 2n + 4 = n + 18 ⇒ n = 14,

Sum = 5(14) + 20 = 90