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Question
Find x.
`((-6)/7)^(x - 7) = 1`
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Solution
We have, `((-6)/7)^(x - 7) = 1`
Using law of exponents,
x0 = 1 ...[∵ a is non-zero integer]
Then, `((-6)/7)^(x - 7) = 1`
It is possible only, if x = 7
So, `((-6)/7)^(7 - 7) = 1`
⇒ `((-6)/7)^0 = 1` ...[∵ a0 = 1]
Hence, x = 7
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