Advertisements
Advertisements
Question
Find x.
`((-6)/7)^(x - 7) = 1`
Advertisements
Solution
We have, `((-6)/7)^(x - 7) = 1`
Using law of exponents,
x0 = 1 ...[∵ a is non-zero integer]
Then, `((-6)/7)^(x - 7) = 1`
It is possible only, if x = 7
So, `((-6)/7)^(7 - 7) = 1`
⇒ `((-6)/7)^0 = 1` ...[∵ a0 = 1]
Hence, x = 7
APPEARS IN
RELATED QUESTIONS
Find the value of 2–3.
The value of (–2)2×3 – 1 is ______.
For any two non-zero rational numbers x and y, x4 ÷ y4 is equal to ______.
55 × 5–5 = ______.
The value of `(1/2^3)^2` is equal to ______.
Express as a power of a rational number with negative exponent.
(25 ÷ 28) × 2–7
Simplify:
`(49 xx z^-3)/(7^-3 xx 10 xx z^-5) (z ≠ 0)`
Find the value of x so that `(5/3)^-2 xx (5/3)^-14 = (5/3)^(8x)`
`(125 xx x^-3)/(5^-3 xx 25 xx x^-6)`
Mass of Mars is 6.42 × 1029 kg and mass of the Sun is 1.99 × 1030 kg. What is the total mass?
